ok so I need to sketch the straight line determined by the points and find the slope intercept equation of the line. (1,1) (2,4) I got everything except the book says the answer is y=3x-2 and im getting y=3x+1?
Okay so you found out the slope is 3.
yea
Then you plugged in the point \((1,1)\):\[ (1) = 3(1) + b \]
i didn't do that.. but im following..
You solved for \(b\):\[ 1-3 = b\implies -2 = b \]Then put it into the original equation: \[ y = 3x-2 \]
oh
can u just tell me what form of the line is that again..? is that point-slope?
I don't know what you mean.
hmm, like. what is the origional equation?
ok, where did you get 1−3=b⟹−2=b from?
actually, i get it. But why not use point (2,4)?
The \(\implies\) is just like saying "the equation becomes this"
You can use any point you want, if it is on the line.
oh ok. Yea, i see the other one would work as well. Thanks!
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