The Element rhenium has two naturally occurring isotopes, 185 Re and 187 Re, with an average atomic mass of 186.207 amu. Rhenium is 62.60% 187 Re, and the atomic mass of 187 Re is 186.956 amu. Calculate the mass of 185 Re. How do you do this?
write the expression as if you were to calculate the average atomic mass, i.e. \(\Sigma (mass_{isotope\;A}*\%abundace_{isotope\;A})\) since: (abundance % of isotope 185) + (abundance % of isotope 187) = 1 you can substitute in: (abundance % of isotope 187)= 1-(abundance % of isotope 185)
I don't get it, where did the one come from?
they have to equal to 100%, 1 is the same as 100% without the percent.
So is the equation 62.60=1-x?
it would be 0.6260=1-x or 62.60=100-x both are equally valid. but that's what you have to substitute into the first equation
Thank you, I understand now!
good stuff. no problem, dude
Join our real-time social learning platform and learn together with your friends!