Question

Please help on derivates of polynomials
I'll post the pic in a bit

Answer 1

\[\Large y=3e^x+\frac{4}{\sqrt[3]{x}}\]Can be written as,\[\Large y=3e^x+4x^{-1/3}\]
Understand that part? :o

Answer 2

3-> -1/3 because of the square root

Answer 3

so, yes? XD

Answer 4

So taking the derivative from there...
Remember the derivative of e^x? :)

The other term you'll want to apply the `power rule` to.

Answer 5

E^x =0????

Answer 6

Noooo silly! :O\[\Large \left(e^x\right)' \quad=\quad e^x\]

Answer 7

Stays the same :O

Answer 8

True story!

Answer 9

So that tells us that the first term won't change when we take the derivative of it.

Answer 10

Do you understand how to apply the power rule to the other term? :)

Answer 11

What do we do with 3

Answer 12

constant coefficients don't affect the differentiation process.. we can ignore them.\[\Large \left(3e^x\right)'\quad=\quad 3\left(e^x\right)' \quad=\quad 3e^x\]

Answer 13

3e^(x)+(-1/3)4x^(-2/3)???

Answer 14

Woops you didn't apply the power rule correctly.
Let's check this out a sec:\[\Large \left(x^{-1/3}\right)' \quad=\quad -\frac{1}{3}x^{-\frac{1}{3}-1}\]\[\Large -\frac{1}{3}x^{-\frac{1}{3}-\frac{3}{3}} \quad=\quad ?\]

Answer 15

-4/3*

Answer 16

yes, good good good.

Answer 17

@zepdrix : so my answer would be 3e^(x)-(4/3) x^(-4/3)

Answer 18

yay good job \c:/

Answer 19

How would I solve a square root problem like this one

Answer 20

@zepdrix

Answer 21

That function is a polynomial.

Answer 22

\[\Large u=\sqrt[5]{t}+4\sqrt{t^5}\]Again, we want to write these as rational expressions.\[\Large u=t^{1/5}+4t^{5/2}\]Understand the crazy magic I pulled there?

Answer 23

in computer science maybe, but not in math.

Answer 24

lol

Answer 25

We're are you getting 5/2?