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Mathematics 7 Online
OpenStudy (anonymous):

Who wants to help me with some Algebra II?? :D

OpenStudy (anonymous):

i would but not good at math lol srry bud

OpenStudy (anonymous):

Lol

OpenStudy (e.cociuba):

Just post the question.

OpenStudy (anonymous):

Which is the graph of f(x) = |x 1| 3?

OpenStudy (e.cociuba):

Is that the absolute value of 1x?

OpenStudy (anonymous):

Sorry, it is -1 and -3

OpenStudy (e.cociuba):

Okay, so f(x) = |x -1| -3, correct?

OpenStudy (anonymous):

Correct

OpenStudy (anonymous):

I hate this section of Algrebra II.

OpenStudy (anonymous):

Me too!

OpenStudy (anonymous):

i got an A in this part

OpenStudy (anonymous):

I just failed a test on this :/

OpenStudy (anonymous):

I hope it gets easier. lol

OpenStudy (anonymous):

lol it deffinetly does @devinthedev

OpenStudy (anonymous):

Anything involving slope makes no sense to me for some reason.

OpenStudy (e.cociuba):

|dw:1379606831398:dw|

OpenStudy (anonymous):

May I ask another one?

OpenStudy (anonymous):

no

OpenStudy (anonymous):

lol

OpenStudy (e.cociuba):

Does that graph make sense to you? Sure.

OpenStudy (anonymous):

Yes it does.

OpenStudy (***[isuru]***):

yo, hence this is an absolute value u have to something like this Absolute value means there r only positive values so u have to make the expression I x- 1 I positive even when the value of x is negative To do that u'll have to substitute x - 1 when x >= +1 -(x - 1) when x< 1 now when x is >= +1 f(x) = x-1 -3 = x -4 when x is < 1 F(x) = -(x-1) -3 = -2 -x You can no w plot these 2 graphs in one plane and it's the answer

OpenStudy (anonymous):

|dw:1379607167416:dw|

OpenStudy (anonymous):

Yes it does.

OpenStudy (e.cociuba):

|dw:1379607420198:dw| Where did you get that from?

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