Avogardro's number? I have to calculate the cost in dollars of a single aluminum atom in the roll of aluminum foil. The only information i received was: the roll (on scale) cost $1.75. The weight of aluminum in the roll is 300 grams. I have no idea how to figure this out, please help!
first convert 300 grams of Al to moles of Al.
so that would be 26.982/300, right? That would come out to 0.08994 moles
no it's the other way around, \(n=\dfrac{m}{M}\)
okay, then it would come out to 11.119
so you have 11.119 moles next you wanna find out many atoms there are in the roll of foil \(n=\dfrac{N}{N_A}\) N=atoms, \(N_A\)=avogadros number, n= moles
so 11.119/6.02*10^23?
nope. n=moles=11.119
\(11.119\;moles=\dfrac{N}{6.022*10^{23}}\)
so to solve that would I just cross multiply or is it not that easy?
yep. it's just algebra
and then (6.022*10^23)*11.119 would be 6.693638 *10 ^24
so that's how many atoms you have, do you know what do after?
I'm not sure how to figure out the price of an atom now.. If the cost is $1.75 would I just divide the 6.69..ect number from that?
yep. just like if 10 jet skies costed $10, and you wanted to find out how much each would cost.
ok, thank you so much for all your help!
no problem dude!
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