Write an equation for a line parallel to x+15=-5y passing through (0,4)
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OpenStudy (anonymous):
first put equation into y=mx+b
then use point slope form
y-y1=m(x-x1)
m=slope
OpenStudy (anonymous):
0=x1
4=y1
OpenStudy (anonymous):
then the expression will look like y-4+m(x-0)
OpenStudy (anonymous):
@twinkieexpress ?
OpenStudy (anonymous):
slope will be -1/5 as it is parallel to the rrquired eqn.so slopes of oth equations wll be same.
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OpenStudy (anonymous):
u r given a point (0,4)
this will be x1 and y1 in the eqn,
(y-y1)=slope(x-x1)
put the values and try it
OpenStudy (anonymous):
How did you figured out the slope was -1/5?
OpenStudy (anonymous):
First substitute the value to make y positive: y=-0.2x-3
then use the gradient equation: (y-y1)=m(x-x1)
where m is the slope and the point is (x1,y1)
and you will get this: y-4=-0.2(x-0)
and after simplifying you get: y=-0.2x+4
OpenStudy (anonymous):
because the slope on the x value is -1/5 when the coefficient of y is 1
OpenStudy (anonymous):
@jim_thompson5910 ?
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jimthompson5910 (jim_thompson5910):
what's the slope of x+15=-5y
OpenStudy (anonymous):
1
jimthompson5910 (jim_thompson5910):
you need to get the equation into y = mx+b form first
OpenStudy (anonymous):
is it y=1/5x+15
jimthompson5910 (jim_thompson5910):
close, but no
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OpenStudy (anonymous):
umm can you help me with it, y intercept form was a sucky thing for me
jimthompson5910 (jim_thompson5910):
start with x+15=-5y and divide both sides by -5 to isolate y
jimthompson5910 (jim_thompson5910):
what you have is close, but it's a bit off
OpenStudy (anonymous):
umm 7=x-3
jimthompson5910 (jim_thompson5910):
hmm how are you getting that?
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OpenStudy (anonymous):
umm im trying to divide andthen divide both sides by -5
jimthompson5910 (jim_thompson5910):
another way to think about it: divide every term by -5 to isolate y
OpenStudy (anonymous):
-1/5-3=y
jimthompson5910 (jim_thompson5910):
getting closer
OpenStudy (anonymous):
ugh
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jimthompson5910 (jim_thompson5910):
you lost x
OpenStudy (anonymous):
y=1/5x-3
jimthompson5910 (jim_thompson5910):
it should be -1/5x - 3 = y
jimthompson5910 (jim_thompson5910):
much better
jimthompson5910 (jim_thompson5910):
oh sry
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jimthompson5910 (jim_thompson5910):
it should be
y = -1/5x - 3
but you pretty much have it (ignoring the typo)
OpenStudy (anonymous):
and whats my next step?
jimthompson5910 (jim_thompson5910):
so what is the slope of y = -1/5x - 3
OpenStudy (anonymous):
-1/5
jimthompson5910 (jim_thompson5910):
so the slope of any parallel line to this one is also -1/5
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jimthompson5910 (jim_thompson5910):
since parallel lines have equal slopes
jimthompson5910 (jim_thompson5910):
the given point is (0,4)
so x = 0 and y = 4
--------------------
we know that m = -1/5, x = 0, y = 4
plug these 3 pieces of info into
y = mx + b
and solve for b
OpenStudy (anonymous):
y=1/5x+4
jimthompson5910 (jim_thompson5910):
the slope is negative, so it should be
y = -1/5x + 4