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OpenStudy (anonymous):
If 0.440mol of a nonvolatile nonelectrolyte are dissolved in 3.50mol of water, what is the vapor pressure PH2O of the resulting solution? The vapor pressure of pure water is 23.8 torr at 25 ∘C .
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OpenStudy (anonymous):
21.14 torr 1 torr = 1 atm \[\frac{ 3.50 mol }{ 3.50 mol + 0.44 mol }= 0.888\] \[0.888*23.8= 21.14torr\]
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