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having trouble with this If f(x) = 15.0cosx, then what is the area enclosed by the graph of the function, the horizontal axis, and vertical lines at x = 0 degrees and x = 90 degrees?
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area under function curve = integral of function
integrate between x = 0 and 90
0 and pi/2
so is it 15sin90-15sin0 or do i drop the 15
keep the 15. it's 15(sin(pi/2) - sin(0))
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i used 15(sin90-sin0) and got it thanks tho
i know it's the same now because you're using a simple trig function. but if the integral gave xsinx from 0 to 90, you'd have to use pi/2 instead of 90 (and make sure your calculator is set to radians and not degrees)
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