Graph the function. Identify the vertex and axis of symmetry.
f(x)= -2x^2+2x-1 I just need help identifying the vertex and axis

Question

Graph the function. Identify the vertex and axis of symmetry.
f(x)= -2x^2+2x-1 I just need help identifying the vertex and axis

jdoe0001 · Answer

you can get the vertex of a parabola like $\bf \large ax^2+bx+c$  at the coordinates of $\bf \left(-\cfrac{b}{2a}\quad ,\quad  c-\cfrac{b^2}{4a}\right)$

anonymous · Answer

What would they be

jdoe0001 · Answer

well, what did you get?

jdoe0001 · Answer

notice that "a" "b" and "c" are just the coefficients
so
a = -2
b = 2
c = -1

jdoe0001 · Answer

$\large f(x)= \color{blue}{-2}x^2\color{blue}{+2}x\color{blue}{-1} $

anonymous · Answer

Okay, I'm trying to work it out

anonymous · Answer

how do you figure out axis

anonymous · Answer

for the vertex is -0.5 , -1.5 right

jdoe0001 · Answer

the axis of symmetry.... just means the line where the parabola mirrors itself
so say... you have a parabola going downwards... let's say a vertex of...hmmm ( -2 , -3)|dw:1379976468033:dw|