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Find the limit as x->0 (sin 2x)/(4x)
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well to use \[\lim_{x \rightarrow 0} \frac{\sin(x)}{x} = 1\] you need the x in the numberator and denominator to be he same so rewrite it as \[\lim_{x \rightarrow 0} \frac{1}{2} \times \frac{\sin(2x)}{2x} = \frac{1}{2} \lim_{x \rightarrow 0} \frac{\sin(2x)}{2x}\]
how did 4x turn into 2x?? .__.
well 1/2 * 1/2x = 1/(2*2x) = 1/4x
why did you use 1/2?
lol i'm lost :(
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why did you use 1/2?
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