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How to prove that In(1+y) + In(1+x) =A that can be written as xy+x+y=C which A and C are constants.
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\[\ln(1+y)+\ln(1+x)=\ln[(1+y)(1+x)]=A \rightarrow (1+y)(1+x)=e^A\]\[(1+y)(1+x)=xy+x+y+1=e^A \rightarrow xy+x+y=e^A-1=C\]Then, the expression is correct if:\[C=e^A-1\]
@CarlosGP
Why there is +1 at xy+x+y+1?
(x+1)(y+1)=xy+x+y+1
Okay.Thanks CarlosGP.
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