Question

Factor the following trinomial completely: x^3 - x^2 - 12x
A. x(x^2 - x - 12)
B. x(x + 3)(x - 4)
C. x(x - 3)(x - 4)
D. x(x + 3)(x + 4)

Answer 1

x^3 - x^2 - 12x
x(x^2-x-12)
x(x^2-4x+3x-12)
x(x(x-4)+3(x-4))
x(x-4)(x+3)

Answer 2

How about

Answer 3

\[\frac{ x^2+x-30 }{ x+6 }\]

\[\frac{ x^2+6x-5x-30 }{ x+6 }\]

\[\frac{ x(x+6)-5(x+6) }{ x+6 }\]

\[\frac{ (x+6)(x-5) }{ (x+6) }\]

\[(x-5)\]

Answer 4

Thank you so much.

Answer 5

Anytime.

Answer 6

\[\frac{ y^2-16 }{ y-4 }\]

\[\frac{ (y+4)(y-4) }{ (y-4) }\]

\[(y+4)\]

Answer 7

I am going to do it on a new question could you help me then?

Answer 8

\[\frac{ x^2-9x-36 }{ x+3 }\]

\[\frac{ x^2-12x+3x-36 }{ x+3 }\]

\[\frac{ x(x-12)+3(x-12) }{ x+3 }\]

\[\frac{ (x-12)(x+3) }{ (x+3) }\]

\[(x-12)\]