Question

f"(x) of 3e^(-x)^(2)
I dont know how to find this. I am using it so that i can use the trapizodial rule

Answer 1

is your question \[f(x)=3e^{-x^2}\]find \(f''(x)\) ?

Answer 2

What is the second derivative?

Answer 3

yes

Answer 4

can you find the first derivative using the chain rule?

Answer 5

I thought it would be 3e^(-x^2)*-6x

Answer 6

if u=-x^2, then du/dx=-2x, so where did the -6x come from?

Answer 7

i did chain rule on it

Answer 8

\[u=-x^2\]\[f(x)=3e^{-x^2}=3e^u\]\[f'(x)=3e^u{du\over dx}\]

Answer 9

what is du/dx ?

Answer 10

Im really not sure.

Answer 11

\[u=-x^2\implies{du\over dx}={d\over dx}(-x^2)=?\]