Question

You have to buy 26 tickets for a baseball game. You have $348 and must spend it all. How many of each type of ticket can you buy? (The front tickets are $18 and the back tickets are $12) pLease provide full explanation.

Answer 1

$348 = front*$18 + back*$12

and

front + back = 26

Answer 2

with the money you have you could buy
29 x $12ticket
and be within your savings,

however, you are supposed to buy 26 tickets
and spend it all
so instead of having left over money, you should upgrade some of the tickets

Answer 3

if you solve the system of equations, you get a collection of 26 tickets
with the highest amount of front tickets that you can get :)

$348 = front*$18 + back*$12
front + back = 26

use substitution or elimination to solve the system of equations
which one do you prefer?

Answer 4

Hey umm well i`m in grade six so can you please explain it in a somple easy way that I can understand. Thanks a lot.

Answer 5

@mathessentials ^^

Answer 6

your in 6th grade so you havnt learned system of equations yet. That is in Algebra 1, so don't worry about that yet

Answer 7

Thanks but can you answer my question? You sound like a great person

Answer 8

i can try. I am okay with systems of equations, so ill solve from where he left off.
f=front b=back
f18 + b12=348
f + b = 26
i am using elimination method btw.
18f+12b=348
-18f-18b=-468
-4b=-120
b=30
then plug 30 into one of the original equations
f+b=26
f+30=26
f=-4
You cant have negative tickets so im not sure what to do there. Sorry, you should leave it blank and ask your teacher. Sorry i took so long i was hoping i would get the right answer but i guess i didnt. :p

Answer 9

@sherry123
Verify for yourself that
{back = 20, front = 6}