Question

Identify the vertex for the graph of y = −3x2 + 6x − 4.

(1, 5)

(1, −1)

(−1, −13)

(−1, −9)

Answer 1

you can find the vertex of a parabola of the type as \(\bf ax^2+bx-c\) at \(\bf \left(-\cfrac{b}{2a}\quad ,\quad c-\cfrac{b^2}{4a}\right)\)

Answer 2

all u need to do is plug in the number
ax^2 is -3x^2
+ bx is + 6x
- c is -4