Can someone help me with linear inequalities please! -2/3y>4
Ok
To get y, multiply by the reciprocal.
(-2/3)(-3/2)y= 4(-3/2)
When you multiply or divide by a negative number in an inequality, you must flip the sign. y<-6
Ok, thank you!! Would it be a problem if you can help me with 2 more problems please.
Ok
Ok, the first is \[\frac{ 1 }{ 5 }y-\frac{ 1 }{ 3 } \le \frac{ 2 }{ 3 }\] and the second one is \[\frac{ 2 }{ 3 }x-5 \le 7\]
1st one You want y by itself so move the -1/3 to the other side.
Do u know how to do that?
After u do that you should have 1/5y less than or equal to 1
Yea, thats what I got. Is that my final answer, because on te back of my book it said the answer would be \[y \le -5\]
Almost. It's 5 where'd u get the neg
oh it's because 1/5y is actual -1/5y, Sorry. lol
Oh. Ok
Do u know what to do on the next one
Would be the same one as the first one?
Sort of give it a shot
The equation is this right 2/3x−5≤7, so I would add 5 to both sides, and that would get \[\frac{ 2 }{ 3 }x \le 7\], right?
Yes
not 7 but 12.
12
Then I would divide both side by 2/3, correct?
Or multiply by the reciprocal 3/2
ok, thank you! You were a big help =)
You're welcome
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