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How many H atoms are present in a 7.98ng sample of caffeine C8H10O2N4?
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\[7.98 ng(\frac{1 g}{1x10^{-9}ng})(\frac{1 mole comp}{194g comp})(\frac{6.022x10^{23}molec}{1 mole comp})(\frac{10 H atoms}{1 molec})=?\]
put that in the calculator and you should get your answer. Also check the molar mass of the compound I googled it because i am lazy.
Zbay can you help me after this please?
Why did you divide 7.98 by 1x10^-9? Shouldn't you multiply it to get grams?
yes flip that
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it should be \[\frac{1x10^{-9}g}{1 ng}\]
okay.. thank you so much! :)
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