Mathematics OpenStudy (anonymous):

Graph (Line) Assignment, Assistance Needed! OpenStudy (anonymous):

Launch Area:___(1, 2)___ Point A:___(1,5)_______ Point B:___(2,4)_______ Point C:__(4,3)________ You must show your work on each question below. 1.Determine the equation of the line, in standard form, that will get your spacecraft from the Launch Area to Point A. 2.Determine the equation of the line, in point-slope form, that will get your spacecraft from Point A to Point B. 3.Determine the equation of the line, in slope-intercept form, that will get your spacecraft from Point B to Point C. 4.In question 2, you selected one of two points (Point A or Point B) to be included in your point-slope equation. Write the point-slope form of that equation again, using the other point’s coordinates. 5.Convert the equations you arrived at in question 2 and question 4 into slope-intercept form. 6.Does the point you select matter when your write a point-slope equation? Explain your reasoning using complete sentences. 7.Reflect back on this scenario and each equation you created. Would any restrictions apply to the domain and range of those equations? Explain your reasoning using complete sentences. 8.Explain, using complete sentences, why it is important to understand any limitations on the domain and range. OpenStudy (anonymous):

I honestly have a hard time understanding these, thus I am posting the question. You don't even have to answer all of them - Just give me the steps by steps on how I can solve it for myself :B OpenStudy (anonymous):

@LaceyLeanne @Country_Boy_Jonathan. @tristan10946 OpenStudy (anonymous):

I went ahead and attached a graph so you can see the visual version. OpenStudy (anonymous):

@texaschic101 Are you still there? OpenStudy (texaschic101):

Launch area (1,2) point A (1,5) first we will find the slope slope(m) = (y2 - y1) / (x2 - x1) (1,2) x1 = 1 and x2 = 2 (1,5) x2 = 1 and y2 = 5 now lets sub m = (5 - 2) / (1 - 1) m = 3/0 = 0 This is a vertical line and has an undefined slope Therefore, if we use (1,2) the equation is x = 1 if we use (1,5), the equation is x = 5 standard form : x + 0y = 5 ================================ Point A = (1,5) Point B = (2,4) find the slope m = (y2 - y1) / (x2 - x1) m = (4 - 5) / (2 - 1) m = -1/1 which is the same as -1 now put it in y - y1 = m(x - x1 form using -1 as m and either of your points. I will use (1,5) y - 5 = -1(x - 1) <-- point slope form ============================== your looking for slope intercept form y = mx + b First find the slope using points (2,4) and (4,3) Once you have found the slope(m), sub it and either points into this formula : y - y1 = m(x - x1) and just solve for x putting it into slope intercept form. ================================ I used (1,5) in question 2, so we need to use (2,4) plug in m = -1 and (2,4) x1 = 2 and y1 = 4 into this equation : y - y1 = m(x - x1) you do not need to solve it, just sub in your values ================================= now we need to solve the equations we found in problems 2 and 4 y - 5 = -1(x - 1) -- solve and put in y = mx + b form y - 4 = -1(x - 2) -- solve and put in y = mx + b form ================================ Either point you choose to use, when solved and put in y = mx + b form, will be the same answer. It does not matter what point you pick. ================================ 7 and 8.....sorry ...don't know them :) OpenStudy (anonymous):

@texaschic101 Thanks! Close + medal OpenStudy (anonymous):

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