Question

PLEASE HELP ?!?!? MATRIX QUESTION!!!

Answer 1

One thing about the multiplicative inverses is if you multiply them you get the identity.

Answer 2

could you show me? I'm still a lil confused with this

Answer 3

Well, do you know how to do matrix multiplication?

Answer 4

no I don't think so

Answer 5

http://assets.openstudy.com/updates/attachments/515c4ceee4b0507ceba37899-e.mccormick-1369021610530-matrixmultiplication.png

Answer 6

I made one small mistake in there I need to fix, but that is the principal of matrix multiplication.

Answer 7

There are two ways to find if two matrices are inverses. 1) Multiply them and see if you get the identity. 2) Take one of them, find its inverse, and see if that is the other one. Both work just fine.

Answer 8

Most inverses do not look much like the original. Option A and D are too similar, so I would test them last. B and C look more different, like inverse pairs normally do, so I would test them first.

Answer 9

So c?

Answer 10

Did you multiply it and see?

Multiplication test:
\(\begin{bmatrix}
a&b\\c&d
\end{bmatrix}
\begin{bmatrix}
e&f\\g&h
\end{bmatrix}
=
\begin{bmatrix}
1&0\\0&1
\end{bmatrix}\)
If that is true, then they are inverses.

Answer 11

For a 2X2 you can just plug it in by positions:

\(\begin{bmatrix}
a&b\\c&d
\end{bmatrix}
\begin{bmatrix}
e&f\\g&h
\end{bmatrix}
=
\begin{bmatrix}
ae+bg&
af+bh\\
ce+dg&
cf+dh
\end{bmatrix}\)

If you just make that right hand side and it becomes \(\left[\begin{smallmatrix} 1&0\\0&1 \end{smallmatrix}\right]\) then you have found the inverse.

Answer 12

Wow my brain is still a little bungled could you walk me through this question? been trying to figure it out since yesterday

Answer 13

Well, you said C. So, if I take the abcdefgh thing, that would be:
\(\begin{bmatrix}
(5)(\frac{1}{2})+(8)(-\frac{4}{5})&
(5)(-\frac{1}{2})+(8)1\\
(5)(\frac{1}{2})+(10)(-\frac{4}{5})&
(5)(-\frac{1}{2})+(10)1
\end{bmatrix}\)

Answer 14

Now, the great thing is, you DON'T have to do all that math. Only need to find one failure and you stop. Well, right there I see a problem.

Answer 15

\(5(-\frac{1}{2})+8\implies -\frac{5}{2}+8\)

That, in the upper right, does not look like 0. Therefore it can't be C.

Answer 16

ok I got it so it's A right? C was my second choice but I wasn't sure

Answer 17

Not A.

I have to head out now. The joys of work... But if you put the others into that formula, you will find one that comes out as the identity matrix.

Answer 18

hmm so beetween B and D