Question

Solve the quadratic equation. (x + 2)2 = 36
A. x = ±6
B. x = 4 and x = -8
C. x = ±√6
D. x = ±√2

Answer 1

first you square root both sides to get
\[x+2=\pm6\]
then put x+2 equal to both -6 and +6
\[x+2=-6\]
\[x+2=6\]
in both you subtract two and get
x=-8 and x=4