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OpenStudy (anonymous):
np
OpenStudy (anonymous):
ok so we got
-4 x -4y -4z = -32
OpenStudy (anonymous):
okay so i thoguht it was -8 x 4 = -32
OpenStudy (anonymous):
I should really. not have used the equal sign.
OpenStudy (anonymous):
before:
-x -y -z = -8
after:
-4 x -4y -4z = -32
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OpenStudy (anonymous):
"before" was taken from the problem
"after" is the line multiplied by 4
OpenStudy (anonymous):
okay i get that now what
OpenStudy (anonymous):
now, we add that new line with the second row
-4 x -4y -4z = -32
-4x +4y +5z = 7
------------------
OpenStudy (anonymous):
so 1z=-25
OpenStudy (anonymous):
the x terms are both negative
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OpenStudy (anonymous):
ohhh so -8x + 1z = -25
OpenStudy (anonymous):
yep :)
OpenStudy (anonymous):
ok now what:D
OpenStudy (anonymous):
Progress so far:
[x] 1. get a second x,z equation by elimination
[ ] 2. add the two x,z equations and get z=
[ ] 3. substitute z in one of the x,z equations
OpenStudy (anonymous):
we now have two x, z equations
-8x + 1z = -25 (just calculated)
2x + 2z = 4 (problem description)
we should add them in such a way that one of the variables is eliminated
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OpenStudy (anonymous):
subtract???????????
OpenStudy (anonymous):
do you want to eliminate x or z first
it doesn't matter which one
OpenStudy (anonymous):
x
OpenStudy (anonymous):
then because one of the X is negative we would add instead of subtract
OpenStudy (anonymous):
-8x + 1z = -25
2x + 2z = 4
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OpenStudy (anonymous):
-6x + 3z = -21
OpenStudy (anonymous):
true
this is a legal operation. HOWEVER, it did not eliminate x :)
OpenStudy (anonymous):
we need to make the Xes the same "size" before adding, to eliminate
OpenStudy (anonymous):
crap ur right
OpenStudy (anonymous):
-8x + 1z = -25
2x + 2z = 4
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OpenStudy (anonymous):
so i multiply
OpenStudy (anonymous):
yes, multiply the second row
by how much?
OpenStudy (anonymous):
the first equation by 2 and the second by 8
OpenStudy (anonymous):
possible. since 2/8 can be reduced to 1/4
you can also multiply the first one by 1 and the second by 4
OpenStudy (anonymous):
-8x + 1z = -25
4(2x) +4(2z) = 4(4)
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OpenStudy (anonymous):
so its
16x + 2z = -50
16x + 16z = 32
OpenStudy (anonymous):
ohh i see ill do it ur way
OpenStudy (anonymous):
yes now subtract
OpenStudy (anonymous):
ok
OpenStudy (anonymous):
when u said " -8x + 1z = -25 4(2x) +4(2z) = 4(4) " <---- is there supposed to be a 4
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OpenStudy (anonymous):
-8x + 1z = -25
8x +8z = 16
OpenStudy (anonymous):
yes, problem was 2x + 2z = 4
OpenStudy (anonymous):
multiply everything by 4, also the 4
OpenStudy (anonymous):
so that is -7z = -41
OpenStudy (anonymous):
?????
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OpenStudy (anonymous):
any of the two that have only x and z
OpenStudy (anonymous):
i would have never noticed that
OpenStudy (anonymous):
2x + 2(1) = 4
OpenStudy (anonymous):
2x + 2 = 4
2x = 2
x=1
OpenStudy (anonymous):
2x + 2z = 4
yes I made an error, though --- z is actually =-1
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OpenStudy (anonymous):
-25 + 16 = -9 and I wrote 9
OpenStudy (anonymous):
yes
OpenStudy (anonymous):
yeah i fixed it x=3
OpenStudy (anonymous):
[x] 1. get a second x,z equation
[x] 2. add the two x,z equations and get z=
[x] 3. substitute z in one of the x,z equations
ok now that we have x and z value
we can just plug those in any of the two first equations to get y
OpenStudy (anonymous):
the first equations according to problem:
-x -y -z = -8
-4x +4y +5z = 7
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OpenStudy (anonymous):
we need an equation that has y in it otherwise we can't solve for y
OpenStudy (anonymous):
looks good
OpenStudy (anonymous):
we can try the values in the other equation:
-x -y -z = -8
-(3) -(6) -(-1) = -8
-3-6+1=8