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Why does the unit of time enter twice in the unit of acceleration?
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Hi, \[acceleration = \frac{ velocity\ difference }{ time taken }\] here velocity difference has the same unit as velocity which is ;\[ms ^{-1}\] so the unit of acceleration should be something like this..... \[acceleration = \frac{ ms ^{-1} }{ s } = ms ^{-1}\times s ^{-1}= ms ^{-2}\] hope this will help ya!!
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