Question

Why does the unit of time enter twice in the unit of acceleration?

Answer 1

Hi,
\[acceleration = \frac{ velocity\ difference }{ time taken }\]
here velocity difference has the same unit as velocity which is ;\[ms ^{-1}\]

so the unit of acceleration should be something like this.....
\[acceleration = \frac{ ms ^{-1} }{ s } = ms ^{-1}\times s ^{-1}= ms ^{-2}\]

hope this will help ya!!