Ask your own question, for FREE!
Mathematics
OpenStudy (littlebird):

Derivative of y=sec^-1(1/t)

OpenStudy (anonymous):

so sec y = (1/t) use implicit differentiation and then find dy/dx.

OpenStudy (littlebird):

I can't get past this

OpenStudy (anonymous):

it's not (sec (1/t))^-1 it's arcsec (1/t).

OpenStudy (anonymous):

that's why you have to rewrite and use implicit differentiation \[y=\sec^{-1} \left( \frac{ 1 }{ t } \right)\Rightarrow \sec y = \frac{ 1 }{ t }\] \[d(\sec y )= d \left( \frac{ 1 }{ t } \right) \Rightarrow (\sec y)( \tan y)\frac{ dy }{ dt }=-\frac{ 1 }{ t^2 } \Rightarrow \frac{ dy }{ dt }=-\frac{ 1 }{ t^2 } \cdot \frac{ 1 }{ (\sec y)( \tan y) }\]

Can't find your answer? Make a FREE account and ask your own questions, OR help others and earn volunteer hours!

Join our real-time social learning platform and learn together with your friends!
Latest Questions
karremat: Does anyone know anything about pesticide like in point forms
15 hours ago 0 Replies 0 Medals
Can't find your answer? Make a FREE account and ask your own questions, OR help others and earn volunteer hours!

Join our real-time social learning platform and learn together with your friends!