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Find y' and y''. y = (ln(4x)) / (x7) I found that y' = (1- 7 ln(4x)) / (x^7) What is y" ?
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denominator is wrong it should be x^15
can the first part in numerator x^7(4/4x) be reduced to x^6 ?
yes
I found that y' = (1- 7 ln(4x)) / (x^7)
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was ur solution
denominator is wrong it should be x^15
3.jpg is ur y'' and is the final answer.
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3.jpg is not correct but thanks for the help. I solved it and got (56 ln 4x - 15)/ (x^9)
can u show me ur steps ?
denominator is wrong it should be x^8. not x^15 and not x^7 as mentioned in y'
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