A rod with density 3+sin(x) lies on the x-axis between x=0 and x=pi. Find the mass and center of mass of the rod.

Question

anonymous · Answer

so here you integrate... from 0 to pi.

$$m = \int\limits_{0}^{\pi}(3+\sin x)dx$$

and the center of mass of the rod is

$$CM = \frac{ 1 }{ m }\int\limits_{0}^{\pi}x(3+\sin x)dx$$

anonymous · Answer

you there?

megannicole51 · Answer

yeah im trying to figure it out sorry

anonymous · Answer

no it's okay.  take your time

megannicole51 · Answer

yay i got the right answers! :D thank you!

anonymous · Answer

you're welcome!

megannicole51 · Answer

how do you find a mass of a triangle? is it the same or different?

anonymous · Answer

what's the density function?

megannicole51 · Answer

hey sorry i fell asleep! so the function is 1+x grams/cm^2 and this is what the pictures looks like that im given....|dw:1380761318589:dw|