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simplify v^-5 . v^3 write answer with positive exponent only
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is there suppose to be a . in the middle
yes i think it means multiply
\[v^{-5}=\frac{ 1 }{ v^5 }\]
v^−5v^3 v^−5+^3 1/^v2
so\[v^{-5}\cdot v^3 = \frac{ 1 }{ v^5 }\cdot v^3 = \frac{ v^3 }{ v^5 }=\frac{ 1 }{ v^2 }\]
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so final answer is 1/v^2
YES
thanks
no problem:)
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