Question

you estimate that your school is 45ft tall. your school is actually 52ft tall. find the error precent

Answer 1

your school is really 52, you estimated 45, so you were short by 7 units

so, what's 7 units in percent of 52? well, \(\large \begin{array}{llll}
\#& \%\\ \hline\\
\cfrac{52}{7} = &\cfrac{100}{x}
\end{array}\)

solve for "x"

Answer 2

So is it 13.46? or did i do it wrong?

Answer 3

tis correct, 7 is 13.46% of 52

Answer 4

Thanks:)

Answer 5

so your estimate was short by 7% of the actual height

Answer 6

you estimate was 7 units or 13.46% of the actual height rather

Answer 7

Oh ok thanks.

Answer 8

yw

Answer 9

Cn u help with this question?....A doctor measures a patient's weight to 162lb to the nearest pound. (Find the maximum possible measurements.)

Answer 10

hmmm.. measurements? I assume it means its height... well.... 162lbs would be someone thin about 5 feet tall I guess

Answer 11

if you mean its weight... well, it's given, 162lbs

Answer 12

yeah...

Answer 13

yeah, your supposed to round to the nearest percent

Answer 14

percent? but we would need a point of reference, all we know is that the patient is 162lbs

lbs = pounds

Answer 15

unless you mean, from lbs to kg

Answer 16

no it doesn't say that.

Answer 17

then is rather ambiguous..... because we have no point of reference
all we can say is that 162lbs is the only amount we have, thus that's 100%

Answer 18

see... dunno --> (Find the maximum possible measurements.) <--- means

Answer 19

oh..