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Mathematics
OpenStudy (anonymous):

determine the number of possible permutations of two of the five vowels: a, e ,i, o, and u. List them all

OpenStudy (anonymous):

ae ai ao au aa ea ee ei eo eu ia ie ii io iu oa oe oi oo ou ua ue ui uo uu

OpenStudy (anonymous):

that's long

OpenStudy (anonymous):

there is 25 possible

OpenStudy (anonymous):

i have that but my problem is that my work doesn't match up.. i'm trying to find the number using a formula and thought that (5 over 2) was the right formula, but that ends up being 10, which would be right if I'm not supposed to count repeats (like ae and ea) but since it says find the permutations i think I am. So i'm not sure what formula is the right one to use

OpenStudy (anonymous):

u do count ae with ea

OpenStudy (anonymous):

yes but what formula gives me 25 as a number? not 5! and not (5 over 2)

OpenStudy (anonymous):

i'm pretty sure i'm missing something really basic, i just can't figure it out

OpenStudy (anonymous):

I remembered!

OpenStudy (anonymous):

there is 5 possible combinations for "a" right?

OpenStudy (anonymous):

aren't there 9 if you count the ones that are switched? aa ae ai ao au ea ia oa ua

OpenStudy (anonymous):

well I'm saying for when a is the first one

OpenStudy (anonymous):

oh, yeah

OpenStudy (anonymous):

so isn't there 5

OpenStudy (anonymous):

ok what about "b" there is 5 right

OpenStudy (anonymous):

yeah

OpenStudy (anonymous):

so, this would go for all 5 of them to its 5+5+5+5+5 or 5x5= 25 got that?

OpenStudy (anonymous):

yes, but that's not really using any equation that actually relates to permutations

OpenStudy (anonymous):

this is a way to show the equation in a more "easy" way

OpenStudy (anonymous):

good job understanding this way, not many people understanding this

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