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OpenStudy (anonymous):

If an object is dropped from a height of 154 feet, the function h(t)= -16t^2+154 gives the height of the object after t seconds. When will the object hit the ground?

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OpenStudy (anonymous):

let h(t)=0 and solve for t..

OpenStudy (anonymous):

May you help me? I forgot how to...

OpenStudy (anonymous):

\[0=-16t^{2}+154\] first transpose 154 to the left side, divide both sides by -16 and get the square root of both sides

OpenStudy (anonymous):

Wouldn't that be a non-real solution?

OpenStudy (anonymous):

Sorry if I'm being stupid...

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OpenStudy (jdoe0001):

\(\bf 0 = -16t^2+154\implies -154= -16t^2\implies 154= 16t^2\) and so on

OpenStudy (anonymous):

Ah, I forgot my negatives. Thank you.

OpenStudy (anonymous):

if you divide a negative by a negative it will be a positive.. right?

OpenStudy (anonymous):

I believe so. I forgot my negative while transposing.

OpenStudy (anonymous):

Sorry.

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