If an object is dropped from a height of 154 feet, the function h(t)= -16t^2+154 gives the height of the object after t seconds. When will the object hit the ground?

Question

anonymous · Answer

let h(t)=0 and solve for t..

anonymous · Answer

May you help me? I forgot how to...

anonymous · Answer

$$0=-16t^{2}+154$$
first transpose 154 to the left side,
divide both sides by -16
and get the square root of both sides

anonymous · Answer

Wouldn't that be a non-real solution?

anonymous · Answer

Sorry if I'm being stupid...

jdoe0001 · Answer

$\bf 0 = -16t^2+154\implies -154= -16t^2\implies 154= 16t^2$

and so on

anonymous · Answer

Ah, I forgot my negatives. Thank you.

anonymous · Answer

if you divide a negative by a negative it will be a positive.. right?

anonymous · Answer

I believe so. I forgot my negative while transposing.

anonymous · Answer

Sorry.