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If an object is dropped from a height of 154 feet, the function h(t)= -16t^2+154 gives the height of the object after t seconds. When will the object hit the ground?
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let h(t)=0 and solve for t..
May you help me? I forgot how to...
\[0=-16t^{2}+154\] first transpose 154 to the left side, divide both sides by -16 and get the square root of both sides
Wouldn't that be a non-real solution?
Sorry if I'm being stupid...
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\(\bf 0 = -16t^2+154\implies -154= -16t^2\implies 154= 16t^2\) and so on
Ah, I forgot my negatives. Thank you.
if you divide a negative by a negative it will be a positive.. right?
I believe so. I forgot my negative while transposing.
Sorry.
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