Question

how do you factor 16x^2-4x-6?

Answer 1

you try to find two numbers that multiply to c (6) and two that add to b (4)

Answer 2

take 2 out as a common factor leaving

\[2(8x^2 - 2x - 3)\]

multiply 8 and -3 then find the factors that add to -2

then you can substitute into binomials

\[\frac{2(8x + factor1)(8x + factor 2)}{8}\]

cancel common factors from the numerator and denominator for the answer

Answer 3

yep that's wat i was going to say