Question

Let f(x) =(4x^{2}-6x+2)(4x^{2}+2x-10). Evaluate f'(x) at x = 1.
can someone break it down for me?

Answer 1

\(f(x) =(4x^{2}-6x+2)(4x^{2}+2x-10)\)

First find f'(x). Use the product rule:

\(y = uv\)

\(y' = uv' + vu' \)

Answer 2

In this case,
let \(u = 4x^{2}-6x+2\) and \(v = 4x^{2}+2x-10 \).
Now find \(u'\) and \(v'\).
Then follow the product rule.