Question

What is the equation of the following graph?

Answer 1

http://roads.advancedacademics.com/contentserver/content/roadssection/279670/questions/assessments/l-determiningquadraticfunctionquiz/a2_1.7_quiz_15.bmp

Answer 2

What is the vertex?

Answer 3

5,1

Answer 4

Plug that into vertex form. Use the root (4,0). Replace x with 4, Replace y with 0. Solve for a

Answer 5

y=ax^2+bx+c that equation?

Answer 6

\[y=a(x-h)^2+k\]

Answer 7

i got a=0/2

Answer 8

i pluged in 5 for h and 1 for k is that right?

Answer 9

That would be 0 and it wouldn't be a parabola.

Answer 10

ok soo then scince its 0 would u plug that for a?

Answer 11

\[0=a(4-5)^2+1\]

Answer 12

Solve for a

Answer 13

a=1

Answer 14

no

Answer 15

hmm let me try again

Answer 16

\[0=a(-1)^{2}+1\]

Answer 17

\[0=a(1)+1\]

Answer 18

\[-1=a\]

Answer 19

ohh haha

Answer 20

yes

Answer 21

A. f(x) = x2 + 10x - 24
B. f(x) = -x2 + 10x - 24
C. f(x) = x2 - 10x + 24
D. f(x) = -x2 + 10x + 24
its not c or a how do i find the rest ? or the equation

Answer 22

Because c and a are not -

Answer 23

y=a(x−h)^2+k

Answer 24

like plug in all of those #

Answer 25

Plug in a, h, and k

Answer 26

ok

Answer 27

Where did the x and y go?
What part of plug in a, h and k do you not understand?

Answer 28

\[y=-1(x-5)^{2}+1?\]

Answer 29

Now expand the binomial and collect like terms and see which choice it is.

Answer 30

i got y=-x2-26
\[y=-1(x^{2}+25)+1 \]

Answer 31

-24* not 26

Answer 32

Perhaps you need to review how to multiply (x-5)(x-5)

Answer 33

sorry had a lagg i would do y=-1(x-5)(x-5)+1

Answer 34

or just y=(x-5)(x-5)