Question

rewrite the equation in vertex form name the vertex and y-intercept
y=x^2-10x+15

A. y=(x-10)^2-10
vertext : (-10,-10)
y-intercept: (0,10)

B. y=(x-5)^2-10
vertex: (5,-10)
y-intercept: (0,15)

C. y=(x-5)^2 + 40
vertex: (5,-10)
y-intercept: (0,15)

D. y=(x-10)^2+20
vertex: (-10,-10)
y-intercept:(0,-10)

Answer 1

y=x2−10+15
y=(x−5)2−25+10
y=(x−5)2−10


this is a graph with a minimum point to the function Y

u will get the minimum value for the y when "x" is equal to 5 'cause when "x" is equal to 5 the term (x-5)^2 will be 0 ....
and the function "y" will equal to -10
For any other value than 5 the term (x-5)^2 will take a positive value and therefor the value of function will increase....
So.. the "x" co-ordinate of the vertex is 5 and "y" cordinate of the vertex is -10
vertex = (5,-10)

and u can find the "y" coordinate "y" intercept when the value of "x" is 0
which is 15
so... the intercept = (0,15)


Hope this will help ya!!!!

Answer 2

so it would be B

Answer 3

YEP !!!

Answer 4

ya got it right XD

Answer 5

okay thanks lol :)

Answer 6

kk :-)