A cessna aircraft has a lift off speed of 107 km/h. What minimum constant acceleration does this require if the aircraft is to be airborne after a take-off run of 276 m?

Question

tkhunny · Answer

Everything is going the same direction.  This makes it a little easier.

Acceleration is Constant

a(t) = M -- Where M is a constant that we do not yet know.

Velocity

v(t) = Mt + v0 -- Where v0 is the initial velocity.  Since we're starting from zero
v(t) = Mt

Displacement

d(t) = ½Mt^2 + D0 -- Where D0 is the starting location.  Since we're starting from a starting line (that should make sense), we get D0 = 0

Thus,

a(t) = M
v(t) = Mt
d(t) = ½Mt^2

Let's stop there and see if you're still with me.