Ask
your own question, for FREE!
Ask question now!
Mathematics
2 Online
OpenStudy (anonymous):
Determine if the following Serie converges or not
\[\Large{\sum_{k\in\mathbb{N}}\frac{(-1)^{k}}{k^{2}+1}}\]
12 years ago
Join the QuestionCove community and study together with friends!
Sign Up
OpenStudy (anonymous):
Alternating series test.
12 years ago
OpenStudy (anonymous):
i know but i couldnt apply it.. can u show me please ? i have exam on wendensday =(
12 years ago
OpenStudy (anonymous):
Well, show the absolute value is always decreasing.
12 years ago
OpenStudy (anonymous):
i think the test is for showing if the serie monoton decreased.. bu
12 years ago
OpenStudy (anonymous):
hmm how to apply it?
12 years ago
Join the QuestionCove community and study together with friends!
Sign Up
OpenStudy (anonymous):
Show \(a_n > a_{n+1}\).
12 years ago
OpenStudy (anonymous):
ok i will make a step but i would be happy if you help me by the next steps..
12 years ago
OpenStudy (anonymous):
Well, the absolute value is always decreasing.
12 years ago
OpenStudy (anonymous):
\[
n<n+1\\
n^2<(n+1)^2\\
n^2+1<(n+1)^2+1\\
\frac{1}{n^2+1}>\frac{1}{(n+1)^2+1}\\
|a_n|>|a_{n+1}|
\]
12 years ago
OpenStudy (anonymous):
\[\Large{\sum_{k\in\mathbb{N}}\frac{(-1)^{k}}{k^{2}+1}=(-1)^{k}(\frac{1}{k^{2}+1})}\] and i think \[\Large{ \frac{1}{k^{2}+1}\geq \frac{1}{(k+1)^{2}+1}}\]
12 years ago
Join the QuestionCove community and study together with friends!
Sign Up
OpenStudy (anonymous):
aah ok.. adn how to plugin it to question so that in exam i can get full points for this question?
12 years ago
OpenStudy (anonymous):
Just invoke the alternating series test.
12 years ago
OpenStudy (anonymous):
ok i will try..
12 years ago
OpenStudy (anonymous):
thank you very much
12 years ago
Can't find your answer?
Make a FREE account and ask your own questions, OR help others and earn volunteer hours! Join our real-time social learning platform and learn together with your friends!
Sign Up
Ask Question
Latest Questions
clllaaaaaire:
CLOSED
2 weeks ago
0 Replies
0 Medals