How would I solve 5y-4y=1/2(3-1)?
\(5y - 4y = \dfrac{1}{2}(3 - 1)\)
So do I do 3-1 first?
Yes, parentheses first always
okay so then we have 5y-4y=1/2(2)
so two times 1/2?
5y-4y=4?
Wait a minute. Are you trying to put the previous problem in point-slope form?
If so, then you have entered numbers incorrectly.
yes...oh
Yeah I'm really bad at this
I plugged in what you gave me on the last question and that's what I cam up with
No, that's not what I said to do. You mis-interpreted me.
oh okay so this was what the questions said: Determine the equation of the line, in point-slope form, that will get your spacecraft from Point A to Point B. Point A: (1,4) Point B: (3,5)
The point-slope form is: \(y-y_1 = m(x-x_1)\) The slope is \(m = \dfrac{1}{2}\) the first point is \((x_1, y_1) = (1,4)\) Thus the equation is: \(y - 4 = \dfrac{1}{2}(x - 1)\)
okay so aren't 5 and 3 the x variables?
No, you can't call numbers variables.
oh okay...So where does the 5 and 3 go?
We don't need the 5 or 3 because they are not part of the point-slope formula
Oh got it...So how do I finish solving?
For the point slope formula, we only need the first point and the slope. We used the 5 and the 3 to calculate the slope, so it's not like we didn't use them.
Okay...So first I need to solve y−4=1/2 (x−1) ?
That's the equation of the line in point-slope form. You don't need to do anything else. That is what they were asking for.
Okay...I think I made it harder than what it needed to be... Thank you so much ^-^
Could you help me with the second part?
Determine the equation of the line, in slope-intercept form, that will get your spacecraft from Point B to Point C. Point B: (3,5) Point C: (5,3)
Okay, did you find the slope yet?
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