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Solve (x/3) + (x/7) < 2
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solve for x
remember the rules of adding fractions? they always have to have the same denominator. so what can you multiply the 3, then the 7 by to have the same denom?
the 3 by 7 and the 7 by 3
7x+3x<42 then 10x<42 x<4.2 thats the answer
ok, so what are you left with on top (on the left side)?
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7x
ok, and what about on top of the second fraction?
3x
add them up
so then it'd be 10x/21
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I understand it from here, I just didn't know how to start the problem :p
ok, hope I helped
you did, thanks!!
no just i said what to do
x/3 + x/7 < 2 Solution:- First we add these fractions whose sum is 10x/21 if we want to check the answer whether i am right or wrong you just divde 10\21 and its answer would 0.4761 0.4761 < 2 Hence proved
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