Question

Use the integral test to determine if the series is convergent or divergent 9/2x-1

Answer 1

\[\int\limits_{t}^{1}\frac{ 9 }{ 2x-1 }\]

Answer 2

woops, t and 1 are switched

Answer 3

I got the integral as being equal to 9(ln(2t-1))

Answer 4

yup

Answer 5

My homework software is saying that's wrong :(

Answer 6

I think you should post the original problem, since you say "the series converge or not" I assume that you have something else

Answer 7

I tried even including the 9(ln1) just incase

Answer 8

the integral give out the number, value of something, not give you the conclusion of converge or diverge. If it is the series or sequence, may be..... who know? may be I can understand what happen

Answer 9

\[\sum_{0}^{\infty} \frac{ 9 }{ 2n-1 }\]

Answer 10

If I don't make mistake, the integral test says "If f is a continuous , positive, decreasing function on [1,infinitive, and \(a_n\) = f(n) for all n, then \(\sum_ {n=1}^{\infty} a_n and \int_1^{\infty} f(x)dx \) both converge or diverge
remember 1 to infinitive, not 1 to t

Answer 11

We were taught to evaluate the limit from 1 to t as t approached infiniti

Answer 12

nope, you confuse with the concept of take limit of the inpropriate integral.

Answer 13

But that's even what our assignment says to do