write an equation of the line that is perpendicular to 6x-5y=7 that passes through the point (-11,5) using point slope form
you need to find the slope first....do you know how to do that ?
do as Hero said and put 6x - 5y = 7 into slope intercept form which is y = mx + b. The position of m is the slope. Can you put it into that form ?
slope = y2-y1/x2-x1 right
that is the slope formula, but we do not have 2 points, therefore, we need that given equation in y = mx + b form
ok cam you show me so i dont make any mistakes. i just want to be sure so i understand
6x - 5y = 7 (subtract 6x from both sides) -5y = -6x + 7 (now divide by -5 to get y by itself) y = -6/-5x - 7/5 y = 6/5x - 7/5 do you understand how I did that ?
yes i do
y = mx + b form and m is your slope, therefore, the slope of this equation is 6/5. However, we are looking for a perpendicular line so the slope we need has to be the negative reciprocal of the slope of the equation. All that means is " flip " the slope and change the sign. slope is 6/5 and the slope we need is -5/6. Understand ?
Yes, now that is how i do the slope form right? Now what about the coordinates and the point slope form?
point slope form is : y - y1 = m(x - x1) slope(m) = -5/6 (-11,5) x1 = -11 and y1 = 5 now sub your info in the formula and what do you get ? You do not have to solve it, just put it in the formula, parenthesis and all.
are you stuck ?
y-5= 6/5(X-(-11)
not quite....we are using the negative reciprocal of the slope 6/5, which is -5/6. So the point slope formula is : y - 5 = -5/6(x -(-11) or you could probably just put : y - 5 = -5/6(x + 11)
Oh ok thank you so much, now i dont want to be a bother but do you mind helping me with other questions :)
possibly...hope they are not geometry related...not good at those
i will post it and we will see i can. Thank you
no problem :)
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