How to find the limits from graph?
just find value of points around the point at which you want to find the limit. take the arbitrary point as close as you can to the point at which you wanna find limit. that would be your value of limit since limit doesn't care what is going at the exact point. limit just tells you what is happening around the point
I want to know the answer of the following
Well ill do one or two and then you'll get it by then :) \(\lim_{x\rightarrow0^-}\) Is very similar to saying that what does the function approach as the x value moves very close from the indicated direction. So if you move your finger along the graph slowly from any negative x value towards zero (since we are approaching from the negative) you will see it approaches the line \(y=5\). So therefore, \[\lim_{x\rightarrow0^-}=+5\]
Similarly if you approach it from the positive x side, you will approach the line of \(y=-5\) so therefore, we say: \[\lim_{x\rightarrow0^+}f(x)=-5\]
WOW !! You are genius ! my teacher tried to make me understand thousand times but failed!
Thanks budy
Hehehe thanks man anytime!
Is this for highschool calc or first year...? or what course is this for?
yes high school calculus !
Ahh I see cool man! If you want, you can "fan me" and whenever you need another question, just tag me like this: "@keithafascalclover"
One more question
@KeithAfasCalcLover
@keithafascalclover please answer another question.
Hey g.dev haha sorry about that I got caught up on something else haha The limits are a little fuzzy at the bottom...can you re-upload?
\[\lim_{x \rightarrow -1}\], \[\lim_{x \rightarrow +1} \], \[\lim_{x \rightarrow 1}\] \[\lim_{x \rightarrow -0}\] \[\lim_{x \rightarrow +0}\] , \[\lim_{x \rightarrow 0}\]
@keithafascalclover
Beauty! haha okay lets get started!
For the first one I assume you mean: \[\lim_{x\rightarrow1^-}f(x)\] not \[\lim_{x\rightarrow-1}f(x)\] So then we notice that the graph is approaching in interesting limit haha. If you try following the graph towards 1 from the negative side, you'll have a little difficulty. We notice that it approaches a big number...REALLY big. In calculus, we use \(\infty\) to represent a really big number. so then we say that: \[\lim_{x\rightarrow1^-}f(x)=+\infty\]
and similarly when the limit is tending x towards negative zero, the graph is reaching at y = -2 so the limit is -2 right?
RIGHT! \[\lim_{x\rightarrow-0}=-2\]
thanks brother may god bless you!
God Bless you too! Just to point out, if: \[\lim_{x\rightarrow a^-}f(x)=\lim_{x\rightarrow a^+}f(x)=L\] Then we can say that: \[L=\lim_{x\rightarrow a}\]
In other words if the limit from the negative is the same as the limit from the positive, then we can drop the positive and negative signs
Good Luck with your studies and god bless!
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