Question

A chemist need 190 milliliters of a 41% solution but has only 33% and 53% solutions available. Find how many milliliters of each should be mixed to get the desired solution.

Answer 1

Let's name the 33% solution A, and the 51% solution B.
We will make a system:
.33A + .53B = .41(190) --> 33A + 53B = 7790
A + B = 190
The first one gives the concentration of each element.
The second gives the total volume.
Solving using subraction:

33A + 53B = 7790
-33A -33B = -6270
0 + 20B = 1520
B = 76 --> A = 190-76=114

So you need 114 mL A and 76 ml B.

Answer 2

okay thanks so do i just supstitute my numbers in that equation to find the answer?