Ask your own question, for FREE!
Mathematics 21 Online
OpenStudy (anonymous):

I will award a medal! I just need to know if I am doing this right.

OpenStudy (anonymous):

Doing what right?

OpenStudy (anonymous):

1.Your friend runs up to you, scared that he is not ready for the upcoming quadratics test. To help him study, you will create four different quadratic functions. Then demonstrate to him how to rewrite each function as a group of factors, if possible. •The function f(x) is a difference of squares. •The function g(x) is a sum of squares. •The function h(x) is a perfect square trinomial. •The function j(x) can only have a GCF factored out of it.

OpenStudy (anonymous):

Yes, that's right.

OpenStudy (anonymous):

this is what I have so far Quadratic equation 1) f(x) = 2x2+3n4+5 Quadratic equation 2) g(h) = 3x4+9+10g2 Quadratic equation 3) h(x) = 25x2+3a2+4b4 Quadratic equation 4) j(x) = 24x+8b2+2a

OpenStudy (anonymous):

are my equations right? Am I doing what the question is asking?

OpenStudy (anonymous):

Yes, exactly!

OpenStudy (anonymous):

okay thank you!

OpenStudy (anonymous):

so now for equation 1) I just factor it?

OpenStudy (anonymous):

No problem!

OpenStudy (anonymous):

Yep.

OpenStudy (anonymous):

okay makes more sense now :-) I really appreciate it!

OpenStudy (phi):

I don't understand this Quadratic equation 1) f(x) = 2x2+3n4+5 what is 3n4 ? how do we know f(x) is a difference of squares ?

OpenStudy (phi):

For The function f(x) is a difference of squares. An example would be: \( f(x)= x^2 - 9 \) both \(x^2\) and 9 are squares. Then demonstrate to him how to rewrite each function as a group of factors, if possible. I think they want you to factor it. we know (a^2 - b^2) = (a+b)(a-b). Use that rule to factor f(x) to get \[ f(x)= x^2 - 9 \\ f(x)=(x+3)(x-3) \]

OpenStudy (anonymous):

OOH! okay! Thank you!

OpenStudy (anonymous):

I had forgotten how to factor the difference of squares

OpenStudy (phi):

can you do The function g(x) is a sum of squares. ?

OpenStudy (anonymous):

I actually need help with that. I changed my exuation for g(x) to X^3+N^3

OpenStudy (anonymous):

Can you walk me through please

OpenStudy (phi):

I think it is ok to use numbers instead of N but remember this: if f(x) is a quadratic, that means it has a term a x^2 where a is any number (except 0) there are no x terms with a bigger exponent than 2. it might have x terms with smaller exponents of 1 or 0 (x^0 is 1) you say *** g(x) to X^3+N^3 *** that is not correct: a quadratic does not have an x^3 term

OpenStudy (anonymous):

oh okay. So could it be X^2+N^2?

OpenStudy (phi):

yes, Let's choose N= 2, so you can say g(x) = x^2 + 4 that is a sum of squares. it will not factor.

OpenStudy (anonymous):

so a sum of squares can't be factored?

OpenStudy (phi):

yes, a sum of squares does not factor

OpenStudy (phi):

The function h(x) is a perfect square trinomial. the way to do this is start with h(x)= (x+4)(x+4) (the factored form) multiply it out to get the "trinomial"

OpenStudy (anonymous):

oh okay. I just wrote that down. It doesn't factor because you can't find the GCF right?

OpenStudy (phi):

right

OpenStudy (anonymous):

so use distributive property?

OpenStudy (phi):

?

OpenStudy (anonymous):

nevermind sorry. I was confused for a second. Is the equation I have right for the perfect square or do I need to multiply instead of add?

OpenStudy (anonymous):

sorry algebra is confusing for me

OpenStudy (phi):

I don't think we need to use a's, b's and n's. Just x and numbers to find a perfect square quadratic, start with h(x)= (x+ 4)(x+4) (or any number you want instead of 4) now multiply (x+4)(x+4) can you do that ?

OpenStudy (anonymous):

yeah. If I did it right, I got x^2+8x^2+16

OpenStudy (anonymous):

So, when doing my work, My very first step would to be to come up with a functi. That function would be (x+number) times (x+number) right? Then I solve for the trinomial. What next?

OpenStudy (phi):

depends what kind of quadratic you want. The function j(x) can only have a GCF factored out of it. this one could be 4x^2 + 4x + 4 you can factor out a 4: 4(x^2+x+1) but x^2 + x +1 won't factor, so that is as much as you can do .

OpenStudy (anonymous):

oh okay. So then since that is all you can do, is that your answer?

OpenStudy (phi):

yes, that is the last question

OpenStudy (anonymous):

That is what I did for the equation I had so I think I had my work right but the equation was wrong.

OpenStudy (anonymous):

can you give me a second? I have one more I need help with

OpenStudy (phi):

*** you had Quadratic equation 4) j(x) = 24x+8b2+2a *** notice there is no x^2 term so j(x) is NOT a quadratic 8b^2 + 2a should not be there. just numbers or a simple x term if you made it j(x) = 24 x^2 +8x + 2 that would work: 2 ( 12x^2 +4x +1) and we can't factor anything else out.

OpenStudy (anonymous):

Oh okay! I will fix that. Can you give me another example of a function with the difference of squares? I want to make sure I know that.

OpenStudy (phi):

a difference of squares means you need two squares (something multiplied by itself) that you subtract. one of the squares has to have x^2 (so that you have a quadratic) so you could use (3x)^2 and 20^2 now square both, and subtract 9x^2 - 400 is the difference of two squares

OpenStudy (anonymous):

Okay thank you! Everything makes much more sense now! Thanks for all of your help :-) I wrote down the examples you gave me and took notes so I have it for the future.

OpenStudy (anonymous):

Thanks for the medal!

Can't find your answer? Make a FREE account and ask your own questions, OR help others and earn volunteer hours!

Join our real-time social learning platform and learn together with your friends!
Can't find your answer? Make a FREE account and ask your own questions, OR help others and earn volunteer hours!

Join our real-time social learning platform and learn together with your friends!