One number is two more than a second number. Twice the first is 4 less than 3 times the second. Find the numbers.
You have two unknowns in two equations. If you write out the equations, then any valid method for solving for two unknowns will work.
hi, if the first number is "x" the second number is " x + 2" and twice the first is " 2x" also... 3 less than 3 times the second no. is " 2(x+2) -3" so... the problem says Twice the first is 4 less than 3 times the second. which means.. 2x = 3(x+2) -4 now solve this for "x" wt will u get ?
x+2=y 2x+4=3y I believe this is what is being asked.... A system of equations?
\[\{x=2+y,2x=3y-4\}\]
@austinL Yes, I need a system of equations. Let me try that.
{x = 10, y = 8}
@austinL I just solved it, and it's not quite working. @robtobey yours is working perfectly. Thank you!
@austinL ummmm... ur second equation seems to have some error bro... the question says.. twice the first number which is "2y" according to ur system of equation is equal to 4 less than thrice the second number... so.... it should be... 2y = 4 - 3(x+2)
Liv_16 Thank you for the medal.
@robtobey Thank YOU for the help =)
@***[ISURU]*** \(2x+4=3y \implies 2x=3y-4\) Both mean "Twice the first is 4 less than 3 times the second. "
Lol, mine is just subtly different than rob's. I put "+4" on the left, and he put "-4" on the right. Though, subtle differences make big changes in mathematics. +1 for you @robtobey @***[ISURU]*** What you have just done is the next step in solving the system of equations. Substitution.
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