Question

- First order differential using integrating factor...

Answer 1

\[x^5 . \frac{ dy }{ dx } = 2 - x^4.y\]

Answer 2

Hi guys/gals :) I need to isolate dy/dx in the beginning, struggling to figure out how?

Answer 3

Put this into y'+qy=q form.
If not in this form, then arrange so it is.

If you are trying to solve this using the integrating factor, I suggest putting it in the form I wrote here.

Answer 4

dy/dx + P(X)Y = F(X) ?

Answer 5

Yep!

Answer 6

Oops I used q twice. lol.

Answer 7

How would you isolate dy/dx tho?

My initial reaction was to swap x^5 and x^4y around?

Answer 8

If that is what you want to do, then divide both sides by x^6

Answer 9

Not multiply by x^5?

Answer 10

*Sorry for my confusion lol*

Answer 11

well y' is being multiplied by x^6...To undo multiplication of x^6 you divide by x^6.
Whatever you do to one side, do to the other though

Answer 12

Oooh, the x on the left is x^5 not x^6 :D

Answer 13

I think the latex is messed on my computer.
It shows x^6 but when I click on the code it shows x^5.
It made my z's and x's look the same the other day...
errr
So yeah x^5.

Answer 14

So:\[\frac{ dy }{ dx } = 2x^5 -x.y ?\]

Answer 15

Did you divide both sides by x^5?
looks like you failed a little on that.