Question

Solve this radical equation

Answer 1

\[\sqrt{x+9}=x-3\]

Answer 2

would it be no real numbeR?

Answer 3

square both sides:\[x+ 9 = (x - 3)^2\]

Answer 4

let me know if i should keep going

Answer 5

then you have x+9=x^2 - 6x +9

Answer 6

yup :)

Answer 7

then make the equation = 0?

Answer 8

yes

Answer 9

Once it's equal to 0 I factored it and got (x-7)(x+0) so would the answer be 7?

Answer 10

yes. and 0 too. they both work.

you an double check by plugging those x's back in:\[\sqrt(x+9) = x-3\]

Answer 11

thank you!

Answer 12

^_^