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Mathematics 7 Online
OpenStudy (rsadhvika):

Help urgent please, some physics some math

OpenStudy (rsadhvika):

OpenStudy (rsadhvika):

@Abhishek619 or anyone

OpenStudy (rsadhvika):

@Loser66 thanks for having a look i have no clue where to start yet

OpenStudy (loser66):

May be I cannot help. Anyway, I am trying

OpenStudy (rsadhvika):

ty i have no hope i can do it myself alone :(

OpenStudy (loser66):

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OpenStudy (anonymous):

y=h+s(cotb) use equations of motion. y=(Vo sin (alpha) (t)+(1/2)(-g)t^2 and also, (Vo cos (alpha)) (t)=d+s get s from there.

OpenStudy (loser66):

so, you can get the time the stone travels.

OpenStudy (rsadhvika):

im trying to digest the equation both..

OpenStudy (loser66):

agree with Abhishek619

OpenStudy (rsadhvika):

i get Loser66's vertical component equations

OpenStudy (loser66):

to me, after getting the time t, apply to distance equation from horizontal line. It says x = x_0 + V_0x t + 1/2 at^2 , where x_0=0, a =0 and X = d+s

OpenStudy (loser66):

and V_0x = V_0 cos 49

OpenStudy (rsadhvika):

how to get time, i didnt get Abhishek's y = h+scot(b) equation sorry :(

OpenStudy (loser66):

hehehe, I go backward.

OpenStudy (rsadhvika):

vertical : y = 20sin(49) - 5 t^2

OpenStudy (rsadhvika):

horizontal : x = 20cos(49)*t

OpenStudy (rsadhvika):

wher to go from here

OpenStudy (anonymous):

what is x? x is the horizontal distance which the particle has covered. what is that? it is the sum of h and s. do you agree?

OpenStudy (rsadhvika):

^^ yes... x = h+s when the stone hits the incline

OpenStudy (rsadhvika):

sorry, x = d+s

OpenStudy (anonymous):

oh sorry! my bad! good going. t=d+s/ (Vo cos (alpha)) substitute t in y=(Vo sin (alpha) (t)+(1/2)(-g)t^2 you get a quadratic equation in terms of 's'. now solve that quadratic equation and get the value of s.

OpenStudy (rsadhvika):

oww it looks easy, ima try

OpenStudy (rsadhvika):

t = (15+s)/(20 cos(49)) y = 20sin(49) - 5 t^2

OpenStudy (rsadhvika):

but 2 equaitons with 3 unknowns : t, y, s ?

OpenStudy (anonymous):

y=h+ s(tan (beta))

OpenStudy (rsadhvika):

ugh im real dumb

OpenStudy (rsadhvika):

t = (15+s)/(20 cos(49)) y = 20sin(49) - 5 t^2 y= 6+ s(tan (30))

OpenStudy (rsadhvika):

3 equations , 3 unknowns anbody can solve lol you're awesome thanks a lot !!!!!

OpenStudy (anonymous):

lol yea. you're welcome!!

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