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6=14.7e^-0.0000385h
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How do you solve this? :(
is the h a unit of measurement?
Yup
The air pressure p(h) (in lb/in2) at an altitude of h feet above sea level may be approximated by the following formula. At approximately what altitude h is the air pressure 6 lb/in2? (Round to the nearest foot.)
ok, take divide both sides by 14.7 and take the natural log (ln) of both sides to get h= #
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wait... so ln(6/14.7)=-0.0000385h?
yes
But then you run into the same problem... e^x = 6/14.7
Until you solve for x, you can't solve for h
\(\bf \large 6=14.7e^{-0.0000385h} \quad ?\)
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mhmm
try getting a number for ln(6/14.7) [my calc says -0.896088024556635] and then divide by -0.0000385
Oh...
FYI h is not a unit of measurement, it is the variable
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