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The revenue R in dollars received from selling x radios is R(x)=x(90-x). What number of radios sold will maximize revenue? What is the maximum revenue?
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help me please
multiply this out and get \[R(x)=90x-x^2\] then the minimum will be at the vertex first coordinate of the vertex is \(-\frac{b}{2a}\) which in your case is \(-\frac{90}{2\times (-1)}=45\)
oops i wrote "minimum" i meant "maximum" sorry
45 is the maximum revenue right? so what would be the answer to the other question?
??
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