Question

Can someone help me fix me assignment:
This is my teachers feedback:
#2 You need to provide in words which properties are being used
#3 You need to provide in words which properties are being used
#4 How does • x^(2/3)=x^1 ?

Answer 1

Can you open the file?

Answer 2

no

Answer 3

1. While simplifying some math work, Peter wrote on his paper that x3 • x3 • x3 • x3 equaled x3+ 3 + 3 +3 . Did Peter simplify his work correctly and completely to a final answer? Would Peter’s work be the same if he were to simplify x3 + x3 + x3 + x3?
⦁ Yes, Peter did simplify his work correctly, because they both simplify to x^12. Peter's work would not be the same because x^3*x^3*x^3*x^3=x(3+3+3+3)=x^12 while the other quation x^3+x^3+x^3+x^3=4(x^3)
2. Simplify the given expression to rational exponent form, justify each step by identifying the properties of rational exponents used. All work must be shown.
= x^(-6/3)= x^(6/3)= x^2
3. Simplify the given expression to radical form, justify each step by identifying the properties of rational exponents used. All work must be shown.
=x^(2/3-4/9)=x^(2/9)=9(squrtx^2)
4. One of your friends sends you an email asking you to explain how all of the following expressions have the same answer.
⦁ x^(2/3)=x^1 (Power to a power)
⦁ x^(1/3+1/3+1/3)=x^1 (Product of like bases)
⦁ 1/x^-1=x^1 (Negative exponent)
⦁ 11sqwrt(x^5*x^4*x^2=x^1 (Product to a power)

Answer 4

is that to confusing.....number one is okay, but I don't know what he means about You need to provide in words which properties are being used in number 2

Answer 5

@ganeshie8

Answer 6

in no 2 i think there is something wrong with question cuz x^(-6/3)=1/x^(6/3)=1/x^2

we have just used property

\[x ^{-a}=1/x^{a}\]

Answer 7

Umm...okay I probably did it wrong then. The x^(-6/3)=1/x^(6/3)=1/x^2 was my response, no a given equation. Do you know what it is suppose to be from what the question is asking?

Answer 8

oh okay. I looked at the assignment agien. Number 2 is given:
\[\frac{ 1 }{ 3\sqrt{x^-6}}\]

Answer 9

I fixed number two:
1 over 3squrt x^-6 is equal to 1 over (x^6)1/3. Now you have to use the rule: (a^b)^c=a^bc. In other words, you change the exponent to -6*1/3=-2. This then gives you 1 over x^2. The last rule you have to use is 1 over a^-b=a^b. This means that 1 over x^-2=x^2.
Am I right?

Answer 10

okay you are absolutely right.. .. cheers for you..!! sorry for late reply

Answer 11

No that's fine... Thanks for coming back ^-^

Answer 12

well now where are you having problems?

Answer 13

umm...number 3

Answer 14

can you do this subtraction? 2/3-4/9?

Answer 15

\[\frac{ x^\frac{ 2}{ 3} }{ x \frac{ 4 }{ 9 } }\]

Answer 16

okay so now use the property \[x ^{a}/x^{b}=x ^{a-b}\]

Answer 17

here a= 2/3 and b=4/9

Answer 18

so do I do 2 divided by 3 and then that's a, and 4 divided by 9, then that's b?

Answer 19

yes then do subtraction a-b

Answer 20

okay so
A=1.5
B=2.25
1.5-2.25=-.75?

Answer 21

it doesn't look right

Answer 22

okay do convert them in to a simple form of decimals

because 2/3 gives us 0.6666 (recurring) just leave them as it is in fraction

so we get 2/3-4/9= 6-4/9=2/9 got it ?

Answer 23

Yeah...

Answer 24

values of a which you have written is wrong.. just don't convert them in to decimals

Answer 25

okay...so do I put that in my calculator, or is 2/9 the final answer?

Answer 26

nope 2/9 is final answer so we get \[x ^{2/9}= \sqrt[9]{x ^{2}}\]

Answer 27

This is number 4:
\[\sqrt[3]{x^{3}}\]
\[x^{\frac{ 1}{ 3 }}* this 2 more \times\]
\[\frac{ 1 }{ x^{-1} }\]
\[\sqrt[11]{x^5*x^4*x^2}\]

Answer 28

for first we have

\[\sqrt[3]{x ^{3}}\] which is equal to x^(3/3)= x^1

Answer 29

Okay..is that Power to a power. I have to name them as well

Answer 30

for second one we have x^(1/3+1/3+1/3)=x^(3/3)=x^1

Answer 31

yes it is

Answer 32

then the third is 1/x^-1=x^1

Answer 33

third one i hope you can do

Answer 34

yes cheers again.. you are right :0 :)

Answer 35

then the 4th is 11sqwrt(x^5*x^4*x^2=x^1

Answer 36

okay just add the powers of x what do you get then?

Answer 37

can you check my original work to make sure I named them right?

Answer 38

i hope you have found the answer of fourth

Answer 39

okay let me see it

Answer 40

isn't the fourth one 11sqwrt(x^5*x^4*x^2=x^1

Answer 41

yes it is i didn't saw your reply.. you have done well job.. :) :)

Answer 42

Thank you so much for all your help, I couldn't have done it without you ^-^

Answer 43

you are most welcome.. i was just leading you..! :)

Answer 44

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