If a .10 M solution of a colored substance has a maximum absorbance at 500 nm and an absorbance of .26 at this wavelength, what will be the measured absorbance of a .20 M solution at 500 nm?

Question

aaronq · Answer

$Abs \propto concentration$

using the beer-lambert law:   $\dfrac{Abs_1}{C_1}=\dfrac{Abs_2}{C_2}$

anonymous · Answer

I have not learned that formula yet

aaronq · Answer

the actual formula is: $Abs=\epsilon*l*C$, i just simplified it

anonymous · Answer

I do not know that formula unless it is like -log(1-decimL)

aaronq · Answer

it's just like Charles' Law: $\dfrac{V_1}{T_1}=\dfrac{V_2}{T_2}$

anonymous · Answer

this question is just to hard I ended up with a number that is totally wrong it was like -12.3784908

aaronq · Answer

plug your numbers into the formula (in my first post).

anonymous · Answer

is there a fractction

anonymous · Answer

500/.26

anonymous · Answer

do I divide it by 50/.2

anonymous · Answer

|dw:1381286378758:dw|

anonymous · Answer

i don't know where the numbers go?

aaronq · Answer

Abs = absorbance

C= concentration

you don't need to use the wavelength (500 nm)

anonymous · Answer

so you are saying
|dw:1381286576187:dw|
equals